(4x-6)^2-8(4x-6)+7=0

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Solution for (4x-6)^2-8(4x-6)+7=0 equation: 



(4x-6)^2-8(4x-6)+7=0

We multiply parentheses

(4x-6)^2-32x+48+7=0

We add all the numbers together, and all the variables

-32x+(4x-6)^2+55=0

We move all terms containing x to the left, all other terms to the right

-32x+(4x-6)^2=-55

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